Determining Water of Crystallization in Copper(II) Sulfate

Determining Water of Crystallization in Copper(II) Sulfate

Objective

To determine the number of moles of water of crystallisation in hydrated copper(II) sulfate by heating it to constant mass.

Background

Hydrated copper(II) sulfate has the formula: CuSO₄·xH₂O.
When heated, it loses water and becomes anhydrous copper(II) sulfate (white powder):
CuSO₄·xH₂O (s) → CuSO₄ (s) + xH₂O (g). By measuring the mass before and after heating, we can calculate the value of x.

Apparatus

– Crucible
– Tripod and pipe-clay triangle
– Bunsen burner
– Heatproof mat
– Tongs
– Balance (2 d.p.)
– Hydrated copper(II) sulfate

Method

1. Weigh the empty crucible. Record the mass.
2. Add about 2-3 g of hydrated copper(II) sulfate. Weigh and record the total mass.
3. Heat the crucible gently for 2 minutes or until the powder turns white.
4. Continue heating if you see any blue crystals remaining and use a glass rod to gently crush the crystals into a powder.
5. Allow to cool, then weigh the crucible and contents.
6. Repeat heating and weighing until a constant mass is achieved.

Results Table

MeasurementMass (g)
Mass of empty crucible + lid 
Mass of crucible + lid + hydrated CuSO₄ 
Mass of crucible + lid + anhydrous CuSO₄ 
Mass of water lost 

Calculations

  1. Mass of hydrated CuSO₄ used =
    2. Mass of water lost =
    3. Moles of anhydrous CuSO₄ = mass ÷ 159.61 g/mol
    4. Moles of water lost = mass ÷ 18.02 g/mol
    5. Mole ratio of H₂O to CuSO₄ =
    6. Value of x (round to nearest whole number) =

1. Why is it important to heat to constant mass?
2. What would happen if the sample was not fully dehydrated?
3. Suggest a reason for any discrepancy between your result and the theoretical value of x = 5.

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